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5x^2+3=453
We move all terms to the left:
5x^2+3-(453)=0
We add all the numbers together, and all the variables
5x^2-450=0
a = 5; b = 0; c = -450;
Δ = b2-4ac
Δ = 02-4·5·(-450)
Δ = 9000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9000}=\sqrt{900*10}=\sqrt{900}*\sqrt{10}=30\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30\sqrt{10}}{2*5}=\frac{0-30\sqrt{10}}{10} =-\frac{30\sqrt{10}}{10} =-3\sqrt{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30\sqrt{10}}{2*5}=\frac{0+30\sqrt{10}}{10} =\frac{30\sqrt{10}}{10} =3\sqrt{10} $
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